Solution for exp-[(x-a)/b]dx with a and b numbers

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Homework Help Overview

The discussion revolves around finding the solution to the integral of the function exp[-(x-a)/b] with respect to x, where a and b are constants. Participants are exploring the correct form of the integral and discussing related expressions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants suggest using substitution to simplify the integral and question the correctness of different expressions related to the integral's solution. There is also a discussion about the form of the exponential function involved.

Discussion Status

Some participants have provided guidance on the integral's solution, while others are questioning the validity of various expressions presented. There is no explicit consensus on the final answer, and multiple interpretations of the integral are being explored.

Contextual Notes

There are mentions of potential confusion regarding the form of the exponential function and the nature of Gaussian integrals, with one participant noting that indefinite Gaussian integrals do not have a closed form expression.

Rajini
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hi

Hi i need to know the soln. for the following integral..

exp-[(x-a)/b]dx...a and b are some numbers...
thanks
 
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Solve it by substitution if u = (x-a)/b
 
So answer would be -b exp[(a-x)/b] + C...
Is this correct!
 
Rajini said:
So answer would be -b exp[(a-x)/b] + C...
Is this correct!

This expression doesn't mesh with what you had up earlier. Do you have e^\frac{x-a}{b} or e^\frac{a-x}{b} ?
 
hi

I have e[-(x-a)/b]...
the soln. is -b*e[(a-x)/b] + C
i.e., -b*e[-(x-a)/b] + C.
i think both the soln. are correct!
 
Your answer is correct.
 
one more

The soln. for a*exp[-(x-b)^2/(2c^2)] is...
a*sqrt(2c)exp[-(x-b)^2/(2c^2)]...
is this correct?
 
I don't think so. Indefinite Gaussian integrals do not have closed form expression.
 

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