MHB Solution given by sum of functions on a PDE

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The discussion focuses on solving the partial differential equation (PDE) given by u_t + u_x = g(x) with initial condition u(x,0) = f(x). The solution is proposed to be of the form u(x,t) = f(x-t) + √(2π)(g*h)(x), where h(x) is the indicator function on the interval [0,t]. The Fourier transform is applied to the PDE, leading to the equation ∂U/∂t + iwU = U(g) with the initial condition U(u)(w,0) = U(f). The main question raised is about correctly applying the initial condition to the transformed solution U(u)(w,t). Clarification on this application of the initial condition is sought to ensure proper solution formulation.
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Consider $u_t+u_x=g(x),\,x\in\mathbb R,\,t>0$ and $u(x,0)=f(x).$ Given $f,g\in C^1,$ then show that $u(x,t)$ has the form $u(x,t)=f(x-t)+\sqrt{2\pi}(g*h)(x)$ where $h(x)=\chi_{[0,t]}(x).$

So we just apply the Fourier transform to get $\dfrac{{\partial U}}{{\partial t}} + iwU = U(g)$ and $U((x,0))=U(f ),$ so by solving the ODE I get $U(u)(w,t)=ce^{-iwt}+\dfrac{U(g)(w,t)}{iw},$ now I'm quite confusing on placing the initial condition, what's the correct way?
 
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I'm quite interested on this one, I want to know how to use the initial condition and plug it into $U(u)(w,t),$ please! :D
 

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