Solution to Sum of Cosines Homework

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Homework Help Overview

The discussion revolves around simplifying the sum of cosines represented as \(\sum_{k=0}^{n-1} \cos(2 \pi fk)\), with participants exploring various mathematical approaches and concepts related to this problem.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using Euler's formula to express the cosine function in terms of exponentials and question how to sum these exponentials effectively. There is also a consideration of whether the series can be treated as a geometric series.

Discussion Status

The discussion is active, with participants offering different perspectives on how to approach the summation. Some guidance has been provided regarding the use of geometric series and the simplification of terms, but no consensus has been reached on a definitive method.

Contextual Notes

There are indications of confusion regarding the inclusion of exponential terms in the geometric series and the proper formulation of the series. The original poster's intent to simplify the sum is clear, but specific constraints or assumptions are not fully articulated.

matlabber
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Homework Statement


I try to simplify to get rid of sum
[tex]\sum_{k=0}^{n-1}cos(2 \pi fk)[/tex]

Homework Equations

The Attempt at a Solution



I discover I shall use euler equation to form:[tex]\sum_{k=0}^{n-1}\frac{1}{2}(e^{2 \pi fki}+e^{-2 \pi fki})[/tex]

but how to sum exponentials?
 
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Aren't those geometric series?
 
but do I include exp() when I do geometric series?
 
You need to express the terms in the form Ark. Use whatever A and r allow you to do this.
 
is it [tex]\frac{1-exp(2 \pi fi)^{t}}{1-exp(2 \pi fi)}[/tex]
 
If by t you mean n, that would be twice the sum of the first term. You might find it a little simpler to start with cos x = Re[eix]. Then you only have one term to deal with and no 1/2's floating around.
 
thank you very much!
 

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