Solve 7 DOF Error in MATLAB with Ode45 - Help from Experts

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    Matlab Ode45
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SUMMARY

The discussion focuses on resolving an error encountered in MATLAB while implementing a 7 degrees of freedom (DOF) simulation using the ode45 function. The primary issue arises from the use of an undefined argument 'x' in the function IMatrix. The solution involves ensuring that the initial condition vector 'x0' is correctly referenced as 'x' within the function to avoid confusion. The code provided includes the necessary calculations for derivatives of Euler parameters and equations, which are crucial for the simulation.

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  • Familiarity with MATLAB programming
  • Understanding of ordinary differential equations (ODEs)
  • Knowledge of Euler parameters in kinematics
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This discussion is beneficial for MATLAB programmers, robotics engineers, and anyone working on simulations involving multiple degrees of freedom in dynamic systems.

ksh5022
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I am writing a program to find 7 degrees of freedom, but I keep getting an error message that "the argument 'x' is undefined". Could somebody please tell me what I am doing wrong?

function dx = IMatrix(t,x,lamda,E)

I1 = 4250;
I2 = 5175;
I3 = 8397;

lamda(1) = 2/(38^.5);
lamda(2) = 5/(38^.5);
lamda(3) = 3/(38^.5);

theta = 15*(pi/180);

E(1) = lamda(1)*sin(theta/2);
E(2) = lamda(2)*sin(theta/2);
E(3) = lamda(3)*sin(theta/2);
E(4) = cos(theta/2);

x0 = [E(1) E(2) E(3) E(4) 0.2 0.7 0.4];

% Derivatives of Euler parameters represented as dx1 - dx4
dx = zeros(7,1);

dx(1) = 0.5*(x(7)*x(2) - x(6)*x(3) + x(5)*x(4));
dx(2) = 0.5*(-x(7)*x(1) + x(5)*x(3) + x(6)*x(4));
dx(3) = 0.5*(x(6)*x(1) - x(5)*x(2) + x(7)*x(4));
dx(4) = 0.5*(-x(5)*x(1) - x(6)*x(2) - x(7)*x(3));

% Derivatives of Euler Equations (w) are replaced with values dx5-dx7

dx(5) = -x(6)*x(7)*(I3-I2)/I1;
dx(6) = -x(7)*x(5)*(I1-I3)/I2;
dx(7) = -x(5)*x(6)*(I2-I1)/I3;

options = odeset('RelTol',1e-8);
[T,X] = ode45(@IMatrix,[0 60],x0,options);

fprintf('---------------------------------------------------')
fprintf('w1 w2 w3 E1 E2 E3 E4 ')
fprintf('---------------------------------------------------')
fprintf(x(1) x(2) x(3) x(4) x(5) x(6) x(7))
 
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You wrote:
Code:
x0 = [E(1) E(2) E(3) E(4) 0.2 0.7 0.4];
Note that x0 is not the same as x. Maybe that should have been x instead of x0.
 

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