Solve a Billiard Ball Physics Problem with Spin and Momentum | 210 g Mass

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Homework Help Overview

The discussion revolves around a physics problem involving a billiard ball with a mass of 210 g, which is struck with spin and bounces off a table. The initial speed is 1.6 m/s at an angle of 60 degrees, and the final speed is 0.8 m/s at an angle of 30 degrees. Participants are exploring how to calculate the change in momentum due to the collision.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate the change in momentum and expresses confusion about the initial setup and the use of vectors. Some participants suggest using vector components and the Pythagorean theorem to find the resultant vector. Others question the relevance of angles in the calculations and discuss the correct method for vector subtraction.

Discussion Status

Participants are actively engaging with the problem, providing hints and corrections to each other. There is a recognition of the need to properly represent vectors and their directions. Some guidance has been offered regarding the use of components and the Pythagorean theorem, but no consensus has been reached on the final calculations.

Contextual Notes

There is a noted lack of information regarding the time data needed for calculating force, leading to questions about whether the problem is missing details or if an alternative approach is required.

Metropolis
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Hi guys, I am new here and I am having a LOT of trouble with this new momentum stuff, which I failed in :cry:

Here's a question:

A billiard ball has mass 210 g. It's hit with spin and bounces off the side of a table. The initial speed of ball is 1.6 ms-1 (at angle of 60 degrees) and its final speed is 0.8ms-1 (at angle of 30 degrees)

1) Find the change in the momentum of ball due to collision

I had trouble even starting the question. I drew the normal between the collision, and did 90-30=60 to find the inside angle and 90-60=30 for the other. Is anyone able to give me a hint on what formula to use? I'm not familiar with this because I usually do the problems with same initial and final speed.
 
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By definition, the change in the linear momentum is
[tex]m(\vec{v}_f - \vec{v}_i)[/tex]

Hint: Try expressing the velocity vectors in terms of components.
 
Thanks for the tip, I tried using it, and I made up a vector component thing, but I think I am totally wrong

http://img95.imageshack.us/img95/1408/vector4sq.jpg

I added 60 and 30, and the angle ended up being 90, so right angle

and I used Pythagoras' theorem, but I think that is not right...like am I supposed to do Vector sum? and find the resultant vector?...it's all so puzzling to me!:-p
 
Last edited by a moderator:
Close! But instead of adding the vectors you need to subtract them. (Hint: Adding the negative of a vector is equivalent to subtracting it.)
 
Does the inside angle have any relevance?

So is the change in velocity just 1.6 + (-0.8) = 0.8 ?
 
Metropolis said:
Does the inside angle have any relevance?
Of course the angle matters.

So is the change in velocity just 1.6 + (-0.8) = 0.8 ?
No! Just redraw your diagram to show the final velocity minus the initial velocity. (These are vectors and must be treated as such.) You are almost there.

Hint: To find the negative of a vector, just flip its direction 180 degrees.
 
I drew this diagram, is it right or not? Does the resultant vector represent the change in velocity or is there more to it than this?

http://img463.imageshack.us/img463/3143/vectordiagram5hh.jpg
 
Last edited by a moderator:
Looks good to me, except that the resultant (the "vertical" arrow) is pointing in the wrong direction. :smile:

V is the final velocity; U is the initial velocity. You drew (correctly) V + (-U). Make sure you draw the resultant correctly.
 
Oh! haha duh! I meant to draw the resultant vector pointing the other way!

Anyways, does this mean that the change in velocity is just -0.8? That can't be right..
 
  • #10
Metropolis said:
Anyways, does this mean that the change in velocity is just -0.8? That can't be right..
It's not. Where do you get that conclusion? Find the resultant (just like you did before).

Hint: If the resultant is the hypotenuse of a right triangle, then the Pythagorean theorem applies.

If all you need is the magnitude of the change in momentum, just find the magnitude of the resultant. But if you need the direction as well, you'll need to use a bit of geometry. (Or use components, like I first suggested.)
 
  • #11
I get confused with this question because I'm referring to other similar problems which don't have a direct right angle

so the change in velocity is 1.789 m.s-1? {from P's theorem}
 
  • #12
Metropolis said:
I get confused with this question because I'm referring to other similar problems which don't have a direct right angle
For those problems, where there's no right angle to make your life easier, use the component method to add/subtract vectors.

so the change in velocity is 1.789 m.s-1? {from P's theorem}
Sounds good to me.
 
  • #13
Thanks a lot for your help Doc Al!

Now I think I can handle the other parts of the question

EDIT: So for the 2nd part of the question, I have a major problem (I think)...it tells me to find the force the side of table applies to ball...question is...F= Change in momentum / change in time...but I was not given any time data...is it because there's another approach to it? Or did this question that my teacher set have something missing? (which sometimes happens)
 
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