mathdad
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Solve the absolute value equation.
|x^2 - 2x| = |x^2 + 6x|
Seeking the first step.
|x^2 - 2x| = |x^2 + 6x|
Seeking the first step.
RTCNTC said:|x^2 - 2x| = |x^2 + 6x|
|x(x - 2)| = |x(x + 6)|
|x||x - 2| = |x||x+6|
[|x||x - 2|]/|x| = [|x||x+6|]/|x|
|x-2| = |x+6|
x - 2 = x + 6
The only solution is x = 0.
IF they have that as a given then you have to expand it out. But for the record [math]|x|^3 = |x| \cdot x^2[/math]. It won't help you to get rid of the absolute value bars.RTCNTC said:What if the same question involves higher powers?
Example:
|x^2 - 2x|^3 = |x^2 + 6x|^3
I will post a few more if needed.topsquark said:IF they have that as a given then you have to expand it out. But for the record [math]|x|^3 = |x| \cdot x^2[/math]. It won't help you to get rid of the absolute value bars.
-Dan