Solve Acceleration Problem: Maggie & Judy 100m Race

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SUMMARY

In the 100m race between Maggie and Judy, both finish in 10.2 seconds, but their acceleration phases differ. Maggie accelerates for 2.00 seconds, while Judy accelerates for 3.00 seconds. The kinematic equation Xf = Xi + V(init)t + 1/2a*t^2 is essential for calculating their accelerations, which must be treated independently due to their differing acceleration times. The final velocities at the end of their acceleration phases must equal the sustained velocities throughout the remainder of the race.

PREREQUISITES
  • Understanding of kinematic equations, specifically Xf = Xi + V(init)t + 1/2a*t^2
  • Knowledge of uniform acceleration concepts
  • Ability to differentiate between independent motion scenarios
  • Familiarity with basic physics principles related to speed and distance
NEXT STEPS
  • Calculate the acceleration of Maggie using her acceleration time and final distance
  • Calculate the acceleration of Judy using her acceleration time and final distance
  • Explore the implications of independent motion in kinematic problems
  • Review additional kinematic equations for varying acceleration scenarios
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for examples of acceleration problems in competitive scenarios.

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Homework Statement


In a 100 m race, Maggie and Judy cross the finish line at the same time, both taking 10.2 s. Accelerating uniformly, Maggie takes 2.00 s and Judy 3.00 s to attain maximum speed, which they maintain for the rest of the race.
What is the acceleration of each sprinter?

Homework Equations


what is the equation to find the acceleration

The Attempt at a Solution



i couldn't understand the problem
 
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As counterintuitive as it may seem, ties do not imply that the final speed is the same. The most general kinematic eqn for circumstances of linear acceleration is:

Xf=Xi+V(init)t+1/2a*t^2,

but in this case the t's in the eqn are different.

We can call them t1 and t2.

The distance covered during t1 and t2= 100m
the velocity at the end of the acceleration phase muct equal the velocity during the sustained phase. See if that helps.

PS: solving the two girls cases are independent.
 

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