SUMMARY
Bobbie has $1.54 in coins consisting of quarters, dimes, nickels, and pennies. The relationships between the coins are defined as follows: he has twice as many dimes as quarters, three times as many dimes as nickels, and an equal number of pennies and dimes. The equations derived from the problem are 0.25q + 0.10d + 0.05n + 0.01p = 1.54, p = d, 0.50q = d, and 0.15n = d. The challenge lies in solving these equations due to multiple variables present in a single linear equation.
PREREQUISITES
- Understanding of basic algebraic equations
- Familiarity with coin value calculations
- Knowledge of variable relationships in algebra
- Ability to solve systems of equations
NEXT STEPS
- Practice solving systems of equations with multiple variables
- Learn about substitution and elimination methods in algebra
- Explore word problems involving coin combinations
- Study linear equations and their graphical representations
USEFUL FOR
Students learning algebra, educators teaching word problems, and anyone interested in enhancing their problem-solving skills in mathematics.
