Solve Algebraic Equation: r > b/(sqrt2-1) = (sqrt2+1)b | Easy Explanation

[rwinston]

Hi

I am working through the superb book "50 challenging problems in probability." I have a slight problem with some of the algebra used in solving one of the problems. The algebra to solve is shown below:

<br /> \frac{r}{r+b}\times\frac{r-1}{r+b-1}=\frac{1}{2}<br />

Since, for b > 0:
<br /> \frac{r}{r+b} &gt; \frac{r-1}{r+b-1}<br />

<br /> \left(\frac{r}{r+b}\right)^2 &gt; \frac{1}{2} &gt; \left(\frac{r-1}{r+b-1}\right)^2<br />

Thus
\frac{r}{r+b} &gt; \frac{1}{\sqrt{2}} &gt; \frac{r-1}{r+b-1}

So (this is the part I have difficulty with):

r &gt; \frac{b}{\sqrt{2}-1} = (\sqrt{2}+1)b

I can't see how the two sides of the = sign can be transformed into each other, or how they are equivalent. Can anyone help with this?

Cheers

 

[da_willem]

Divide both sides with \sqrt{2}+1 work the product in the denominator to yield one, and you'll see.

 

[HallsofIvy]

I would have multiplied both sides by \sqrt{2}-1!

 

[matt grime]

But surely better than to verify, is to understand how to transform things like this in the future. It is rationalizing the denominator.