Solve Arithmetic Series: Find Sum & Term - Check Answers!

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Homework Help Overview

The discussion revolves around solving problems related to arithmetic series, specifically finding the sum of a series and determining specific terms within a sequence. Participants are examining the calculations and reasoning behind their answers.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the formula for the sum of an arithmetic series and the calculation of specific terms. There is confusion regarding the application of formulas and the correctness of answers provided in the textbook.

Discussion Status

Some participants are offering guidance on the arithmetic series formulas and pointing out potential errors in calculations. There is an ongoing exploration of whether the original poster's answers align with the expected results, and clarification is sought regarding the specific term versus the sum of terms.

Contextual Notes

There is mention of discrepancies between the answers calculated by participants and those found in the textbook, raising questions about the reliability of the provided solutions. Additionally, there is a need for clarity on whether the focus is on finding a specific term or the sum of terms in the sequence.

Aya
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OK, these questions are supposed to be really easy, but I keep geting the wrong answer and I don't understand why, could someone pleas look at my work and tell me what I am doing wrong?

Find the indicated sum of each arithmetic series

S15 for 4 + 11 + 18 + ...

Sn= n/2 [ 2a + ( n - 1 ) d ]
Sn= 15/2 [ 2(4) + (15 - 1 ) 7 ]
Sn= 7.5 [ 8 + 98 ]
Sn= 795

Find t8 for the following sequence

10 000 , -5 000 , 2 500 , -1 250 ,

So...

tn= ar ^ n-1
tn= 10 000 (-0.5) ^ n-1

t8= 10 000 (-0.5) ^ 7
= 78.125


Sometimes the answers in the back of the book are wrong, so am I wrong or are they??
 
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Aya said:
Find the indicated sum of each arithmetic series

S15 for 4 + 11 + 18 + ...

Sn= n/2 [ 2a + ( n - 1 ) d ]
Sn= 15/2 [ 2(4) + (15 - 1 ) 7 ]
Sn= 7.5 [ 8 + 98 ]
Sn= 795

Presumably you not that if an has initial value a0 and "constant difference" x, then an= a0+n(xn. Furthermore, the sum of the first n terms of an arithmetic series is [itex]a_0+ a_n= (a_0+ x_n)n/2[/itex]. That is, the sum is n times the "average" of the first and last terms of the sequence.
In the first problem, a0= 4 and r= 11- 4= 7. The first term is 4 and the 15th term is 4+ 14(7)= 4+ 98= 102. The sum is (4+ 102)/2= (106)/2= 53.
 
HallsofIvy said:
Presumably you not that if an has initial value a0 and "constant difference" x, then an= a0+n(xn. Furthermore, the sum of the first n terms of an arithmetic series is [itex]a_0+ a_n= (a_0+ x_n)n/2[/itex]. That is, the sum is n times the "average" of the first and last terms of the sequence.
In the first problem, a0= 4 and r= 11- 4= 7. The first term is 4 and the 15th term is 4+ 14(7)= 4+ 98= 102. The sum is (4+ 102)/2= (106)/2= 53.

Uhm , the sum should be 53 times 15 (terms of the sequence) = 795. You seem to have dropped out the 15 somewhere. :smile:
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@Aya: You did the first problem correctly :wink:.
The second one, however is wrong. By the way, are you trying to find the 8-th term of the series? Or the sum of the first 8 terms?
Assuming that you want to find the 8-th term, there's a small error in your work: you seem to forget a minus sign. :smile:
 
^ ok, thanks for all your help
 

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