Solve Chain Torque Problem: Find Distance from Left Chain

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SUMMARY

The discussion focuses on solving a torque problem involving a horizontal uniform board supported by vertical chains. The board weighs 125N and is 4m long, with a person weighing 500N sitting on it. The tension in the right chain is 250N, leading to a calculated tension of 375N in the left chain. To find the distance from the left chain where the person is sitting, the torque about the left chain must be balanced by equating the clockwise and counterclockwise moments.

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Homework Statement


A horizontal uniform board of weight 125N and length 4m is supported by vertical chains at the ends. A person weighing 500N is sitting on the board. The tension in the right chain is 250N.
How far from the left chain is the person sitting?


Homework Equations





The Attempt at a Solution


Well I've calculated that the left chain has a tension of 375N as to be able to hold the person-board system in equilibrium. But now they want to know how far the person is from the left chain. I know this requires the balancing of torque, but I'm not sure how.
Thanks for helping out!
 
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Now take the torque about the left.
Consider the man sitting at a distance x from the left end.
Equate clockwise moment and counterclockwise moment to find x.
 

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