Solve Circuit Questions: 5k Ohm Internal Resistance & 2000 kW Peak Power Output

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SUMMARY

The discussion centers on two key electrical engineering problems: converting an electrical meter with a 5k Ohm internal resistance to a 1000 range voltmeter and analyzing supply line losses when changing voltage from 480V to 240V for equipment with a peak power output of 2000 kW. To achieve the desired voltmeter range, a series resistance of 995 kOhm must be added. Additionally, the change in voltage will result in a supply line loss ratio of 4:1, indicating that losses will increase significantly when the voltage is reduced.

PREREQUISITES
  • Understanding of Ohm's Law
  • Knowledge of electrical resistance and series circuits
  • Familiarity with power calculations in electrical systems
  • Basic concepts of voltage and current relationships
NEXT STEPS
  • Calculate series resistance for different meter ranges using Ohm's Law
  • Explore the impact of voltage changes on power loss in electrical systems
  • Learn about the principles of electrical meter calibration
  • Investigate methods for optimizing supply line efficiency
USEFUL FOR

Electrical engineers, technicians working with measurement instruments, and professionals involved in power distribution and efficiency optimization will benefit from this discussion.

CL39
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1. An electrical meter has an internal resistance of 5k Oh, and registers full scale of 50 microA. How many mega Ohm to insert in series to turn meter into a 1000 range voltmeter?

2. An electrical supply line loading question. Some large piece of electrical equipment ahs a peak power output of 2000 kW. If this is maintained, but voltage changed from 480V to 240V, by what ratio will supply line losses change


Thank you.
 
Last edited:
Physics news on Phys.org
Are you a meter man?
 
As opposed to a meter maid?
Why isn't this posted in the Homework section? Does anybody ever read the rules?
 

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