Solve de Moivre's Theorem: Sin 3x & Cos 3x

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SUMMARY

The discussion focuses on applying de Moivre's Theorem to derive expressions for sin 3x and cos 3x, resulting in the identities cos 3x = cos³ x - 3 cos x sin² x and sin 3x = 3 cos² x sin x - sin³ x. The participants confirm that the tangent identity tan 3x = (3 tan x - tan³ x) / (1 - 3 tan² x) is valid. They also solve the cubic equation t³ - 3t² - 3t + 1 = 0 by identifying roots related to the values of x where tan(3x) = 1, ultimately finding the roots as tan(π/12), tan(5π/12), and tan(9π/12).

PREREQUISITES
  • Understanding of trigonometric identities
  • Familiarity with de Moivre's Theorem
  • Knowledge of solving cubic equations
  • Basic skills in manipulating algebraic expressions
NEXT STEPS
  • Study the derivation of trigonometric identities using de Moivre's Theorem
  • Learn how to solve cubic equations using the Rational Root Theorem
  • Explore the implications of tangent identities in trigonometric equations
  • Investigate the periodic properties of trigonometric functions
USEFUL FOR

Students and educators in mathematics, particularly those studying trigonometry and algebra, as well as anyone interested in solving complex trigonometric equations.

  • #31
Well... I think so...
 
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  • #32
sooyong94 said:
Well... I think so...

Can't think why not. You've found three roots with the trig identity that you correctly got through deMoivre. They all work. Cubic equations have a maximum of three roots. We've disposed of the idea t=1 is one of them. Can't think of what else could go wrong.
 
  • #33
Thanks then. :D
 
  • #34
sooyong94 said:
Thanks then. :D

Very welcome.
 

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