Solve Drawbridge Problem: Will Cable Break Before Lancelot Reaches End?

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Homework Help Overview

The problem involves a drawbridge scenario where Sir Lancelot rides onto a bridge that is supported by a cable at an angle. The cable has a specific tension limit, and the question is whether it will break before Lancelot reaches the end of the bridge, given the weights involved.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using Newton's second law and torque concepts to analyze the forces and distances involved. There are questions about how to determine the distances relevant to the forces acting on the system.

Discussion Status

Some participants have provided insights into calculating torques and balancing forces, suggesting a focus on the hinge point for analysis. However, there remains uncertainty about applying these concepts and determining the necessary distances.

Contextual Notes

Participants express confusion regarding the application of formulas and the setup of the problem, indicating a need for clarification on the assumptions and definitions related to the forces and distances involved.

the whizz
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Homework Statement



1.Sir Lancelot rides out of the castle at Camelot and onto the 12.0 m long drawbridge that passes over the moat. Unbeknownst to him, his enemies have partially severed the cable (60° angle with the horizontal) holding up the front end of the bridge so that it will break under a tension of 5000N. The bridge weighs 1900 N and it is uniform. Lancelot, his lance and armor and his horse have a combined weight of 5800 N. Will the cable break before Lancelot reaches the end of the drawbridge? If so, how far from the castle will he be when the cable breaks? (measure from the castle to the center of mass)


The Attempt at a Solution




looking at this I am not really too sure. I may have to use Newtons 2nd law to set up equation. Not sure how to possibly go about finding the distance away he would be when the cable broke.
 
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It's a torque question.
Starting from the hinge work out the force * distance for each component.
Weight of bridge * middle + weight knight * distance downward = force on ropes vertically * length.
 
ok...I don't really understand where the distances come from or how to apply any formula to this problem.
 
Torque is force (at right angles) * distance - eg. when something is trying to turn.
Then it just like balancing forces on a see-saw (teeter-totter)
So you just pick a point to calculate the torques about - it doesn't matterwhere but the axle is an obvious place.

For the weight of the bridge you could imagine summing the weight of each tiny area at a distance X from the hinge - or it's fairly obvious that this equals the weight * half the length, ie the weight acting at the mid point.

Then you also have the weight of the horse + knight at a distance 'd'

To balance these two downward torques you must have an upward one - the ropes are acting at the end of the bridge so the distance is the full length of the bridge.
 

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