Solve Exponents Question: 333333/33 Remainder Value

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TheExibo
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If you divide 333333 by 33, what is the value of the remainder?

I'm not sure where to starte since this number can't be put into a calculator. Is there something with logs? I was thinking of bringing the number down with logs to 333log333, but I'm confused as to where that will lead me.
 

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TheExibo said:
If you divide 333333 by 33, what is the value of the remainder?

I'm not sure where to starte since this number can't be put into a calculator. Is there something with logs? I was thinking of bringing the number down with logs to 333log333, but I'm confused as to where that will lead me.
Taking the logarithm of [itex]333^{333}[/itex], divided by 3, would give 333log(333)- log(3). The difficulty is that your calculator can only give a limited number of decimal places for the logarithm and multiplying by 333, then taking the exponential of the result, will make the "round off error" worse.
 
Do you know modulo arithmetic? You should look into that. (It's not very difficult, it's mainly just a handy notational system to make problems like these easier)