MHB Solve for A_n: Fourier Coefficient $$u_y(x,\pi) = 0$$

Dustinsfl
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$$
u_y(x,\pi) = \frac{x}{\pi} + \sum_{n = 1}^{\infty}nB_n\sin xn\cosh\pi n = 0.
$$
How can I solve for $A_n$ here?
 
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dwsmith said:
$$
u_y(x,\pi) = \frac{x}{\pi} + \sum_{n = 1}^{\infty}nB_n\sin xn\cosh\pi n = 0.
$$
How can I solve for $A_n$ here?

Hi dwsmith, :)

You you mean \(B_n\) ? There is no \(A_n\) in the equation.

Kind Regards,
Sudharaka.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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