MHB Solve for J and B: Junhao & Bala Stamps Problem

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Junhao and Bala collect stamps, with the relationship between their collections defined by two equations. Junhao has 76 more stamps than Bala, leading to the equation J = 76 + B. Additionally, 1/3 of Junhao's stamps equals 3/5 of Bala's, resulting in J = (9/5)B. By substituting the first equation into the second, both J and B can be solved. This method clarifies the approach to finding the number of stamps each collector has.
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Junhao and Bala both collect stamps. 1/3 of Junhao's stamps is equal to 3/5 of Bala's stamps. Junhao has 76 more stamps than Bala. How many stamps does each of them have?

My answer:

Number of stamps Junhao have =J
Number of stamps Bala have = B

We know that Junhao has 76 more stamps than Bala => Junhao = 76 + Bala.

I'm not sure if this is a correct way to do it, but we know 1/3 of Junao's stamp equal to 3/5 of Bala's stamps.
so => (1/3)J = (3/5)BI got stuck and couldn't figure out a clear way to do this.
 
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Johnx said:
Number of stamps Junhao have =J
Number of stamps Bala have = B

We know that Junhao has 76 more stamps than Bala => Junhao = 76 + Bala.

Why don't you change the equation to following using J and B

$$J = 76 + B$$

and you already have the following equation,

$$ \frac{J}{3} = \frac{3B}{5} \implies J = \frac{9B}{5}$$

now you have two unknown variables and two equations. So you can find the values for J and B by substituting the J on the first equation from the second
 
BAdhi said:
$$ \frac{J}{3} = \frac{3B}{5} \implies J = \frac{9B}{5}$$
Thank you for this. I didn't see it this way.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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