Solve for x: 4^(x-5) = 7^(2x-1) | Equation Help

[Nikolas7]

Help me with the following equation:
${4}^{x-5}$=${7}^{2x-1}$

 

[kaliprasad]

Help me with the following equation:
${4}^{x-5}$=${7}^{2x-1}$

you can take log on both sides and get $(x-5)\log\, 4 = (2x-1) log\, 7$ and because it is linear equation you can proceed to finish it

 

[Nikolas7]

Please, show details how you got (x−5)log4=(2x−1)log7

 

[kaliprasad]

Please, show details how you got (x−5)log4=(2x−1)log7

this is as per definition $\log\,a ^ x = x \log\, a $

 

[Nikolas7]

Yes, I figured out, thanks