Solve for y in 16y2 -24xy -300y +x2 + 400x = 0

[vanmaiden]

solving for "y"

Homework Statement

Solve for y in 16y² -24xy -300y +x² + 400x = 0

Homework Equations

N/A

The Attempt at a Solution

16y² -24xy -300y +x² + 400x = 0
16y² -24xy -300y = -x² - 400x
y (16y - 24x - 300) = -x² - 400x

When I get here, I can isolate the y but not the y

 

[Mark44]

Homework Statement

Solve for y in 16y² -24xy -300y +x² + 400x = 0

Homework Equations

N/A

The Attempt at a Solution

16y² -24xy -300y +x² + 400x = 0
16y² -24xy -300y = -x² - 400x
y (16y - 24x - 300) = -x² - 400x

When I get here, I can isolate the y but not the y

What you are calling y and y are the same thing, so you have not isolated y.

The equation is quadratic in y, so you can solve for y using the Quadratic Formula.
16y² -24xy -300y +x² + 400x = 0
<==> 16y² + (-24x - 300)y + (x² + 400x) = 0

This is now in the form ay² + by + c = 0. Can you take it from here?

 

[hunt_mat]

What mark44 is saying is that your equation is a quadratic in y, and there is a formula for those.

 

[Mentallic]

What mark44 is saying is that your equation is a quadratic in y

The equation is quadratic in y

lol

 

[hunt_mat]

Perhaps I should have read mark44's post a little more closely...

 

[vanmaiden]

Thank you all for the help

Can you take it from here?

I see what I should do now, but I continue to get weird answers when I plug it into the quadratic formula. I'm sure it's just too early for me to be doing this stuff lol. I'll continue trying.

Thank you

 

[Mark44]

Not sure what you mean by "weird answers," but there will be two solutions for y, both involving x.