Solve Force & Motion Homework: Find Stretch of Spring w/ 2 & 3 kg Masses

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SUMMARY

The discussion focuses on solving a physics problem involving a 2.0-kg mass and a 3.0-kg mass connected by a massless spring with a spring constant of 140 N/m on a frictionless surface. A 15-N force is applied to the larger mass, and the objective is to determine the stretch of the spring. The correct answer is 4.3 cm, derived from the equation F = -kx, where the total force acting on the system must be accurately accounted for without including vertical forces that do not affect horizontal motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with Hooke's Law (F = -kx)
  • Basic knowledge of forces acting on a system
  • Ability to solve equations involving mass and acceleration
NEXT STEPS
  • Review the principles of Newton's second law (F = ma)
  • Study Hooke's Law in detail, focusing on spring constants
  • Learn how to analyze forces in a system with multiple masses
  • Practice solving problems involving frictionless surfaces and internal forces
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone seeking to deepen their understanding of force and motion, particularly in systems involving springs and multiple masses.

Cantworkit
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Homework Statement


A 2.0-kg mass and a 3.0-kg mass are on a horizontal frictionless surface connected by a massless spring with spring constant k = 140 N/m. The large mass is on the right of the spring: the small mass on the left. A 15-N force is applied to the large mass. How much does the spring stretch? The book answer is 4.3 cm.


Homework Equations


F = -kx
F = ma
W = mg


The Attempt at a Solution



Total force on the system is 15 N
2 kg + kx + 3 kg = 15 N
2 (9.8) + 140 x + 3 (9.8) = 15 N
Somehow I am getting the signs wrong because I cannot come up with 4.3 cm.
 
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Cantworkit said:
Total force on the system is 15 N
Good.
2 kg + kx + 3 kg = 15 N
2 (9.8) + 140 x + 3 (9.8) = 15 N
Not sure what you're doing here:
(1) The weights of the masses act vertically, not horizontally; they aren't relevant to this problem.
(2) The spring force is internal to the system, so it's net effect on the system as a whole cancels out.

Hint: Answer these questions:
What's the acceleration of the system?
What forces act on the larger mass?
 

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