Solve Fusion & Einstein Homework: Energy Output & Mass Conversion

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SUMMARY

The discussion focuses on calculating the energy output and operational duration of a human body powered by fusion energy, specifically using the mass-energy equivalence formula E=mc². The average human mass is considered to be 80 kg, with only 0.7% of this mass (0.56 kg) being convertible to energy, resulting in an energy output of approximately 5.04x1016 Joules. The calculations indicate that if the entire mass were utilized for fusion, the operational lifetime would extend to approximately 1.06 billion years, assuming a continuous energy output of 121 Watts.

PREREQUISITES
  • Understanding of mass-energy equivalence (E=mc²)
  • Basic knowledge of fusion processes, specifically 4H->He fusion
  • Familiarity with power calculations in Watts
  • Ability to perform unit conversions and dimensional analysis
NEXT STEPS
  • Research the principles of nuclear fusion and its applications in energy generation
  • Learn about advanced calculations involving mass-energy equivalence in different contexts
  • Explore the implications of fusion energy on human longevity and sustainability
  • Investigate the efficiency of fusion reactions and their potential for practical energy solutions
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This discussion is beneficial for physics students, energy researchers, and anyone interested in the theoretical applications of fusion energy in human biology and longevity.

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Homework Statement


The energy output of an average person is about 121 Watts. Suppose the average human has a mass of 80 kg and it could run on fusion power by converting only .7% of its mass into energy.
1) how much energy would be available to the body through fusion?
2) How long could the body operate on fusion power (in years)?


Homework Equations


E=mc2


The Attempt at a Solution


Question involves 1)...i completed the problem, but realized that i may have made an error. in the first step i multiplied 80kg by .007 or .7% to get a value of .56 kg that could be used in fusion. I then plugged that into E=mc^2 and calculated a value of 5.04x10^16 J. Now does anyone think that for one i am instead being asked to calculate what energy is available if the average human could use its whole weight (80Kgs) in fusion? The rest of my work is bellow i would greatly appreciate if someone could give it a once over! thanks pf!


unknown burned = 121W/5.04x10^16J/kg = approx. 2.401x10^-15 kg/s

lifetime=(1.00)(80kg/2.401x10^-15 kg/s) = approx. 3.332x10^16s

answer: 1.06x10^9 years
 
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Now does anyone think that for one i am instead being asked to calculate what energy is available if the average human could use its whole weight (80Kgs) in fusion?
Relax - the problem is assuming that 80kg of hydrogen fuel is available to power the body.
In 4H->He fusion, only 0.7% of the proton mass is converted to energy - then all the fuel is converted into He: none left to burn.
 
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