Solve Incline Problem: Find Highest Point Reached by Block

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Homework Help Overview

The problem involves a block moving up a frictionless incline at an angle of 60 degrees with an initial velocity of 2 m/s. The objective is to determine the highest point reached by the block.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the highest point by calculating the distance traveled and the height using trigonometry, but encounters difficulty in determining the acceleration due to a lack of time information. Some participants suggest using conservation of energy as a potential approach, while others discuss the acceleration due to gravity and its components along the incline.

Discussion Status

Participants are exploring different methods to approach the problem, including conservation of energy and kinematics. There is a mix of suggestions and clarifications regarding the forces acting on the block and the relationship between kinetic and potential energy, but no consensus has been reached yet.

Contextual Notes

The discussion highlights the need for trigonometric considerations when relating the height to the distance traveled up the incline. There is an emphasis on understanding the forces acting on the block and the implications of using different methods to solve the problem.

milkyway11
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question says: a block is given an initial velocity of 2m/s up a frictionless plane inclined at 60 degree to the horizontal. what is the highest point reached by the block?

I tried to figure out how to solve the problem by thinking in order to find the highest point, i need the distance it traveled then I can use the sin to find the height. However, in order to find distance traveled, I will have to find the acceleration up the incline and this is where I get stuck. I tried to use kinematics to find the acceleration knowing final velocity will be 0, but I don't know the time spent traveling so I can't solve for acceleration!

Please help me solve it!
 
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Use conservation of energy.

At the top, the kinetic energy is 0 so it is all potential energy. At the bottom, it is all kinetic (if you set V=0 at that point). The two values are equal...hence 1/2 mv^2 at bottom = mgh at top, but that h is the vertical height, so you need to use trigonometry to find the distance up the incline...
 
Of course, the acceleration (if you do not know the conservation of energy theorem) is easy enough to find. The only force acting down the block is the accelaration due to gravity (taking into account trigonometry to find it's component down the incline...)
 
thank you, this helps a lot!

Berko said:
Use conservation of energy.

At the top, the kinetic energy is 0 so it is all potential energy. At the bottom, it is all kinetic (if you set V=0 at that point). The two values are equal...hence 1/2 mv^2 at bottom = mgh at top, but that h is the vertical height, so you need to use trigonometry to find the distance up the incline...
 

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