MHB Solve ln(x-1)/x-3=2 | Step-by-Step Guide

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The discussion focuses on solving the equation ln((x-1)/(x-3))=2. The user struggles to derive the correct solution, initially arriving at x = 2/(e^2-1) but needing clarification on how to reach the lecturer's solution of (3e^2-1)/(e^2-1). Key steps include converting the logarithmic equation to exponential form and rearranging terms to isolate x. The correct manipulation leads to the quadratic form, allowing the application of the quadratic formula for the final solution. The conversation emphasizes the importance of proper algebraic manipulation in solving logarithmic equations.
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hi , hope someone can help as i can't get past a certain step
the natural logs is the problem
ln(x-1/x-3)=2
i can get to this point here -1=x(e^2-1)-3
but the lecturer gave a solution of

3e^2-1/e^2-1 = 3.313035285 how do i get to this

the solution i got was this 2/e^2-1 =0.3130352855
 
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Okay, we are given:

$$\ln\left(x-\frac{1}{x}-3\right)=2$$

Converting from logarithmic to exponential form, we have:

$$x-\frac{1}{x}-3=e^2$$

Multiply through by $x$:

$$x^2-1-3x=e^2x$$

Arrange in standard quadratic form:

$$x^2-\left(e^2+3\right)x-1=0$$

Applying the quadratic formula, we obtain:

$$x=\frac{e^2+3\pm\sqrt{\left(e^2+3\right)^2+4}}{2}=\frac{e^2+3\pm\sqrt{e^4+6e^2+13}}{2}$$

This agrees with:

W|A - ln(x-1/x-3)=2
 
sorry this is what i meant , i wrote the equation the wrong way

this is the correct way

hi , hope someone can help as i can't get past a certain step
the natural logs is the problem
ln⁡((x-1)/(x-3))=2
i can get to this point here -1 = e_x^2-x-3
-1+3=x(ⅇ^2-1)
2 = x(ⅇ^2-1)
2/((ⅇ^2-1) )=x((ⅇ^2-1)/(ⅇ^2-1))
X = 2/(ⅇ^2-1)
the solution i got was this x= (2/(ⅇ^2-1)) → 0.3130352855

but the lecturer gave a solution of
(3ⅇ^2-1)/(ⅇ^2-1) = 3.313035285 how do i get to this
 
$$\ln\left(\frac{x-1}{x-3}\right)=2$$

$$\frac{x-1}{x-3}=e^2$$

$$x-1=xe^2-3e^2$$

$$x-xe^2=1-3e^2$$

$$x(1-e^2)=1-3e^2$$

$$x=\frac{1-3e^2}{1-e^2}$$

$$x=\frac{3e^2-1}{e^2-1}$$
 
hi , in your 3rd line of work where did the 2nd (e^2) come from
thanks
 
$$\frac{x-1}{x-3}=e^2$$

$$x-1=e^2(x-3)$$

$$x-1=xe^2-3e^2$$
 
thank you i could not see that brilliant
 

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