Solve Mass Homework w/ Pullys: Is it Uniform?

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SUMMARY

The discussion centers on determining the uniformity of a pulley with a diameter of 12 cm and a mass of 2 kg. By measuring the time it takes for a 1 kg textbook to fall 1 meter (0.71 seconds), the user calculated the acceleration to be 3.97 m/s². The tension in the system was found to be 5.83 N, leading to a torque of 0.350 N*m on the pulley. The calculated moment of inertia of the pulley was 0.0053 kg*m², which differs from the moment of inertia of a uniform disk (0.0036 kg*m²), confirming that the pulley is not uniform.

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  • Understanding of Newton's second law (F=ma)
  • Knowledge of torque and moment of inertia
  • Familiarity with kinematic equations
  • Basic principles of rotational dynamics
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  • Study the relationship between torque and angular acceleration in rotational systems
  • Learn about the properties of different pulley systems and their applications
  • Explore the derivation of moment of inertia for various shapes
  • Investigate the effects of non-uniform mass distribution on rotational motion
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Homework Statement


You've been given a pulley for your birthday. It is a fairly big pulley 12 cm in diameter and with mass 2kg. You get to wondering if the pulley is uniform. To find out, you hang a 1kg textbook 1.0 meters above the floor and use a stopwatch to measure the time it takes it to fall (.71 seconds). What can you conclude about the pully


Homework Equations


t= r x F
t = I\alpha
F= ma


The Attempt at a Solution



I solved for the acceleration of the books

1.0 = .5a(.71)^2
a= 3.97 m/s^s

Then used force equation on the book with a mg down and T up (axises are pointing down and to the right)

mg- T = ma
T= m(g-a) = 5.83N

Since the tension is equal to the force of on the pully I used it to find the torque on the pully

t= r x F
t=(.06)(5.83) = .350 N*m

I used to the torque to solve for Moment of Inertia using the other torque equation

t= I( a/r)
t(r/a)= I = .0053 kg*m^2

Then I solved for Moment of Inertia of a uniform disk
I= 1/2Mr^2
I=.5(2)(.06)^2 = .0036 kg * m^2

Since the two moments on inertia are not the same the pully is not uniform. Is that correct?
 
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Your calculation is correct.
 

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