Solve ODE with Fractional Term: Find Solutions

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SUMMARY

The discussion focuses on solving the ordinary differential equation (ODE) represented by the equation 2d²u/dx² + (1/2)Lu = 0, where L is a function of x. The user seeks clarification on how to handle the term L in the context of ODEs, particularly in forming the characteristic equation. The derived characteristic equation is 2λ² + Lλ = 0, which is essential for finding the solutions to the original ODE. The discussion emphasizes the importance of transforming the equation to facilitate solution finding.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with characteristic equations in differential equations
  • Knowledge of fractional terms in mathematical equations
  • Basic calculus, specifically differentiation and integration
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  • Study methods for solving ordinary differential equations with variable coefficients
  • Explore the application of characteristic equations in ODEs
  • Learn about the implications of fractional terms in differential equations
  • Investigate numerical methods for approximating solutions to complex ODEs
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Mathematicians, engineering students, and researchers involved in solving differential equations, particularly those dealing with variable coefficients and fractional terms.

knockout_artist
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Member advised to post homework-like problems in the homework sections
Hi,

This is equation I need to find solutions for
d2u/d2x + 1/2Lu = 0 where L(x)

I understand we can remove fraction from second term.
2 [d2 u/d2x ] + Lu = 0

now how do I find solution of this equation ?

How do we deal with L ? because usually we have Y'(dy/dx or in this case du/dx ) or Y (in this case u) in second term in an ode.

Thanks.
 
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knockout_artist said:
d2u/d2x + 1/2Lu = 0 where L(x)
something seems missing here?
 
ok we have to make characteristic equation out of it so I think

from this
2d2u/d2x + 1/2Lu = 0

following equation comes
2 + Lλ = 0
 

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