Solve Preimage Function & Find x-1=e^-x Solution [-2,2]

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SUMMARY

The discussion focuses on solving the equation x - 1 = e^(-x) within the interval [-2, 2]. Participants analyze the behavior of the function at specific points, noting that at x = 0, the left side equals -1 while the right side equals e^(-1), which is greater than -1. Additionally, at x = 2, the left side equals 1 and the right side equals e^(-2), which is less than 1. This indicates that the solution exists within the interval, prompting further exploration of the preimage function concept.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Familiarity with the concept of preimages in mathematical functions
  • Basic knowledge of solving equations involving real numbers
  • Ability to analyze function behavior over specified intervals
NEXT STEPS
  • Study the properties of exponential functions and their graphs
  • Learn about preimage functions and their applications in mathematics
  • Explore numerical methods for finding roots of equations
  • Investigate the Intermediate Value Theorem and its implications for continuous functions
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Students, mathematicians, and anyone interested in understanding the behavior of functions and solving equations involving exponential terms.

shrody
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1.My first problem revolves around the preimage of a function. I have never truly understood this concept, if anyone can clear this with a simple example I would appreciate it.
2.Does x-1=e^-x a solution in the interval [-2, 2] have?
 
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German? You are putting all your verbs at the end of the sentence!:devil:

It's pretty easy to see, isn't it, that when x= 0 x-1= -1 and [itex]e^{-x}= e^{-1}> -1 while if x= 2, x-1= 1 and e^{-2}= .1356< 1.[/itex]
 

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