The discussion focuses on solving a ratio word problem involving work done by two groups of men. The equation derived from the problem is \(\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}\). Participants clarify the total work done by each group, with the first group consisting of (x-3) men working for (2x+1) days and the second group consisting of (2x+1) men working for (x+4) days. The key question raised is whether the numerator should be \(y(2x+1)(x-1)\) or \(y(2x+1)(x-3)\).
PREREQUISITESStudents, educators, and anyone interested in mastering algebraic problem-solving, particularly in the context of work-rate and ratio problems.
kuheli said:hi ,
this is one simple math but i am not getting the answer.
the work done by (x-3) men in (2x+1) days and the work done by (2x+1)men in (x+4) days are in the ratio of 3:10.find the value of 'x'.
Amer said:suppose the amount of work done by a man per day is y
(x-3) men done y(x-3) per day, and y(x-3)(2x+1) per (2x+1) days
Total work done by the first group is y(x-1)(2x+1)
In same manner the other group will do y(2x+1)(x+4)
we have to solve this equation
\frac{y(2x+1)(x-1)}{y(2x+1)(x+4)} = \frac{3}{10}