Solve Rock Problem Part 2: Time to Push 50Kg Rock 10m

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Homework Help Overview

The problem involves determining the time required to push a 50 kg rock over a distance of 10 meters with a given acceleration of 0.16 m/s². This falls under the subject area of kinematics.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss which kinematic equation is appropriate for the problem, with one suggesting the first equation due to the available information. There is also a request for assistance in rearranging the equation to solve for time.

Discussion Status

The discussion is focused on identifying the correct kinematic equation and substituting known values into it. Some participants have provided guidance on the equation setup, while others express uncertainty about rearranging the equation for the desired variable.

Contextual Notes

Participants note that the initial velocity is 0 m/s, which is relevant for the equation being used. There is an emphasis on the need to solve for time, but no consensus on the final steps has been reached.

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This is the second hardest question on my test, how long does it take to push a rock 10m.

50Kg rock
10 m is the distance
0.16m/s2 is the acceleration

Does anyone know which kinematics equation I should use for this problem.
 
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The four kinematic equations are:

d = vi*t + 1/2*a*t2

vf = vi + a*t

vf2 = vi2 + 2*a*d

d = vi + vf/2 *t

You want to pick the equation that has a "t" in it, and the one that has the most of your information already provided.

P.S. your initial velocity is 0 m/s, remember! :wink:
 
I know its the first equation since i have all the information except for t, but I'm not good at rearranging question so can you help me just a bit more. Really appreciate it.
 
ok, so let's substitute the values for what we "know"

d = vi*t + 1/2*a*t2, which would equal:

10 = (0)*t + 1/2*(.16)*t2

we want to try and solve for t, in the first part of the equation, (0)*t, we know that equals 0, so we can get rid of that part, now our equation is:

10 = 1/2*(.16)*t2

can you take it from there?
 

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