Solve Rocket & Lighthouse Problems: Height, Speed, Distance | HW Help"

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SUMMARY

The discussion addresses two physics problems involving kinematics. The first problem calculates the time taken for a model rocket to reach a height of 3.9 meters with a final speed of 28.0 m/s, requiring the use of equations such as \(v_f = v_i + at\) and \(v_f^2 = v_i^2 + 2a(x_f - x_i)\). The second problem involves determining the distance of a ship from a lighthouse using trigonometric functions, specifically \(\tan\theta = \frac{opposite}{adjacent}\), given the height of the lighthouse and the sailor's eye level. Both problems emphasize the application of fundamental physics equations and trigonometry.

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  • Knowledge of basic trigonometric functions
  • Ability to manipulate algebraic equations
  • Familiarity with units of measurement (meters, feet)
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  • Learn about trigonometric ratios and their applications in real-world problems
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  • Explore the concept of vectors in physics for more complex motion analysis
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Homework Statement


Problem 1: A model rocket rises with constant acceleration to a height of 3.9 meters, at which point its speed is 28.0 m/s. How much time does it take for rocket to reach this height? What was magnitude of rocket's acceleration? Find the height and speed of the rocket after 0.10 seconds after launch.

Problem 2: A lighthouse that rises 49 ft above the surface of the water sits on a rocky cliff that extends 19 feet from its base. A sailor on a boat sights the top of the lighthouse at 30 degrees above the horizontal. If the sailor's eye level is 14 feet above the water, how far is the ship from the rocks?

Please help. Much appreciated!


Homework Equations





The Attempt at a Solution

 
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Relevant equations are here:
\cos\theta=\frac{adjacent}{hypotenuse}
\sin\theta=\frac{opposite}{hypotenuse}
\tan\theta=\frac{opposite}{adjacent}
v_f=v_i+at
x_f=x_i+.5(v_i+v_f)t
x_f=x_i+v_it+.5at^2
v_f^2=v_i^2+2a(x_f-x_i)
Move and equate variables as needed. a is a problem specific constant for all equations.
 
Thank you
 

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