I take it you know [itex]\cot u=\frac{\cos u}{\sin u}[/itex]. We could express this in a whole lot of ways. So you may want to give us the entire question or the expression you are working towards.
As rockl.freak667 and Cyosis said, there are many different ways to "break up" such a function? What, exactly, was the statement of the problem?
I think I would be inclined to write it as cot(3u)= cot(u+ 2u) and use "sum" formulas. That's because I don't happen to remember offhand the "triple angle formula" rock.freak667 mentioned!