Solve Trig Problem: Horizontal Dist. Between Truck & Dock to Nearest Tenth

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SUMMARY

The discussion focuses on solving a trigonometric problem involving a loading ramp, a loading dock, and a tractor trailer. The ramp is 2.8 meters long, with one end resting on a dock 0.7 meters high and the other on a truck 1.2 meters high. The user initially misapplies the Pythagorean theorem to a non-right triangle, leading to an incorrect calculation of the horizontal distance. The correct approach involves recognizing the geometry of the situation without relying on the ground as a reference.

PREREQUISITES
  • Understanding of the Pythagorean theorem
  • Basic knowledge of right triangles
  • Familiarity with trigonometric concepts
  • Ability to visualize geometric relationships
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  • Study how to apply the Pythagorean theorem correctly
  • Learn about non-right triangles and their properties
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Students studying trigonometry, educators teaching geometry, and anyone interested in solving real-world mathematical problems involving angles and distances.

Liam C
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Homework Statement


A loading ramp is 2.8m long. One end rests on a loading dock 0.7 meters above the ground, and the other end leads into the back of a a tractor trailer 1.2m above the ground. Find the horizontal distance between the back of the truck and the loading dock, to the nearest tenth of a meter.

Homework Equations


a² + b² = c²

The Attempt at a Solution


In order to solve this problem I figured out that you need to make an imaginary hypotenuse from the ground below the truck to the top of the loading dock. With that hypotenuse you need to figure out the horizontal distance between the back of the truck and the loading dock.
Attempt:
Let x represent the diagonal from the ground at the truck to the loading dock.
2.8^2 - .7^2 = x^2
√6.4 = √x^2
2.53m = x
That is for the imaginary hypotenuse. Now for the leg it asked for:
Let h represent the horizontal distance between the back of the truck to the start of the dock.
2.53^2 - .7^2 = h^2
6.4 - .49 = h^2
√5.91 = √h^2
2.43m = h
Then the therefor statement. The problem is, the textbook tells me the answer is 2.8. Where did I go wrong?
P.S
To get a mental image, just imagine a rectangle with a diagonal from the lower left corner to the upper right corner.
 
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What do you need the ground and this imaginary hypotenuse for? Have you drawn the situation?
 
fresh_42 said:
What do you need the ground and this imaginary hypotenuse for? Have you drawn the situation?
Yes, I have drawn it. You need the hypotenuse because the length it is asking me to solve requires it.
https://www.physicsforums.com/attachments/101935
math.png
 
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So you want to find ##h##. But ##h## can also be found at another place. This should simplify your calculation. Maybe you see it better, if you only think of the truck, the ramp and the dock. You don't need the ground.

Edit: Your error is that you apply Pythagoras on a triangle which isn't a right one.
 
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fresh_42 said:
So you want to find ##h##. But ##h## can also be found at another place. This should simplify your calculation. Maybe you see it better, if you only think of the truck, the ramp and the dock. You don't need the ground.

Edit: Your error is that you apply Pythagoras on a triangle which isn't a right one.
Ohhh, okay I think I can solve it from here, thank you.
 

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