Solve X Equation for Sum of Forces in X/Y Direction

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SUMMARY

To solve for the sum of forces in the x and y directions, one must first identify all forces acting in each direction. The x components of these forces are determined using trigonometric functions, specifically cosine for the adjacent side of a right triangle. The net force in the x direction is calculated using the equation ΣFx = F1x + F2x + F3x + ..., where each F1x, F2x, etc., represents the x components of the individual forces. This method also applies to the y direction using the corresponding y components.

PREREQUISITES
  • Understanding of vector components in physics
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with Newton's laws of motion
  • Ability to draw and interpret right triangles
NEXT STEPS
  • Study the application of Newton's second law in two dimensions
  • Learn how to decompose vectors into components using trigonometry
  • Explore examples of force diagrams and free-body diagrams
  • Investigate the effects of frictional forces on net force calculations
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Students in physics, engineers working on motion analysis, and anyone involved in mechanics or dynamics will benefit from this discussion.

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How do you set up equations for sum of forces in the x and y directions? I can do the y when it is only moving in the x direction, but I don't know how to set up the x equation.
 
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Yes, of course, you can do the "y direction when it is only moving in the x direction" because that's trivial! I'm not sure what you really meant.

Normally one starts with "movement in a line" where we only have to worry about one direction. If something is moving on the x-axis with a force in the x-direction then vx= at+ v0 and x= (1/2)at2+ v0t+ x0.

Now you have motion in the plane (or 3 dimensions with x, y, z) so you have to separate everything into x, y, z components. If you are given "initial velocity" or "force vector" as length and direction, then you need to use trigonometry to decompose into x and y components. For example if the problem says "the initial speed is 20m/s at a direction 30 degrees above the x-axis, draw a picture showing a line at 30 degrees above the x-axis. Mark off a "length" of 20 on that line and draw a perependicular from that point to the x-axis. You see a right triangle with hypotenuse of length 20, "near side" along the x-axis (so its length is x), and "opposite side" parallel to the y-axis (so its length is y). Remembering that "sine" is defined as "opposite over hypotenus", sin(30)= y/20 or y= 20sin(30). Remembering that "cosine" is defined as "near side over hypotenuse", cos(30)= x/20 or x= 30 sin (30).
Once you have those components, you can just work with "x" and "y" separately- that's the nice thing about using components.
 


To solve for the sum of forces in the x direction, you will need to use the concept of vector components. This involves breaking down each force into its x and y components, and then adding them together to find the net force in the x direction.

To set up the x equation, you will first need to identify all the forces acting in the x direction. These forces could include applied forces, frictional forces, and any other forces acting in the x direction.

Next, you will need to determine the x component of each force. This can be done by using trigonometric functions such as cosine, which relates the adjacent side of a right triangle to the hypotenuse.

Once you have determined the x components of all the forces, you can add them together to find the net force in the x direction. This can be represented as:

ΣFx = F1x + F2x + F3x + ...

Where ΣFx represents the sum of all the forces in the x direction, and F1x, F2x, F3x, etc. represent the x components of each individual force.

Using this equation, you can solve for the net force in the x direction and use it to determine the acceleration or motion of the object in that direction.

In summary, to set up equations for sum of forces in the x direction, you will need to identify all the forces acting in that direction, determine their x components, and then add them together to find the net force. This approach can also be used for the y direction, but with the y components of the forces instead.
 

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