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ehrenfest

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**[SOLVED] Griffiths Problem 3.28**

## Homework Statement

Please stop reading unless you have Griffiths E and M book.

In this problem, I found that the approximation agrees with the exact potential. I am not sure what to conclude about higher multipoles. Are they all identically zero or do they all cancel? Is there something about this charge distribution that makes that happen? Could I have predicted that without calculating it?