Solving 12V Battery Problem with Resistors

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Homework Help Overview

The discussion revolves around a circuit problem involving a 12V battery and multiple resistors, including both series and parallel configurations. Participants are tasked with calculating the current through and voltage across each resistor in the circuit.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the calculation of total resistance and current, with some questioning the assumptions made about the configuration of the resistors. There is discussion about using Ohm's law (V=IR) to find voltage drops and currents through individual resistors.

Discussion Status

Some participants have provided guidance on calculating total resistance and current, while others are attempting to clarify how to find voltage drops and individual currents. Multiple interpretations of the circuit setup are being explored, but there is no explicit consensus on the approach yet.

Contextual Notes

There are indications of confusion regarding the arrangement of the resistors, particularly whether they are in series or parallel, which affects the calculations. Participants are also working under the constraints of homework rules that may limit the type of assistance they can provide.

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Homework Statement


A schematic diagram incorporates a 12V battery in series with a 3.0 ohm resistor. The current then flows through 12 ohm and 4.0 ohm resistors in parallel with each other.
a) calculate the current through and voltage across each resistor. 3.0ohm 4.0 ohm 12ohm 24ohm 4.8 ohm 4.0 ohm


Homework Equations


V=IR I=V/R


The Attempt at a Solution


Would I simply plug these into the equation and get an answer?
12/3=4A, 12/4=3A, 12/12=1A, 12/24=.5A, 12/4.8=2.5A 12/4=3A
For voltage would I just plug these answers into the V=IR equation.
 
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You need to find the total resistance of the parallel pair of resistors, with that you can find the total circuit resistance. Once the total resistance is known you can find the total current. Given the current you can now compute the voltage drops. Given the voltage drop on the parallel network you can compute the individual resistance.
 
I got the total resistance and it's 8. How do I calculate the current through each resistor not the total current.
 
You could use V = IR. With your original equations:
12/3=4A, 12/4=3A, 12/12=1A, 12/24=.5A, 12/4.8=2.5A 12/4=3A
You are assuming that all resistors are hooked up in parallel. Which is not the case, so they can't all have 12V across them. Find the total resistance, solve for total current, and then solve for all voltage drops. Once you know voltage drops, you can work out individual currents.
 
I got the total resistance to be 8. The total current to be 1.5 because 12/8=1.5, now how do I get the voltage drops?
 
Well since you now have a circuit with one equivalent resistance in series with the voltage source and you know the total current, just work backwards. For example if your equivalent resistance contained the total resistance of R1+(R2||R3). We would work backwards by splitting up the equivalent resistance into two series resistors (with respect to the voltage source). One resistor would be R1 and the other would be R2||R3. Knowing the total current we can find the voltage drop across R1 and R2||R3 (R2 and R3 will have the same voltage drops because they are parallel).
 

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