- #1

subzero0137

- 91

- 4

Relevant equations:

V=IR

Attempt at solution:

When the switches are open, R1, R2 and R3 are in series so the current in that case would be 12 V/ (2 ohms + 3 ohms + 3 ohms) = 1.5 A. When the switches are closed, the current across R3 is still 1.5 A, so the voltage drop across R3 is 1.5 A * 3 ohms = 4.5 V. I don't know how to calculate the voltage drops across other resistors and the currents through them. How do I proceed? I know we can ignore R2 when the switches are closed since it gets shorted, and I know R and R3 are in parallel when the switches are closed.