Solving (3+cos2θ)dx/dθ = xsin2θ for x

[chwala]

Homework Statement

Solve and obtain an expression for x in terms of θ given $(3+ cos 2θ) dx/dθ = x sin 2θ$

Homework Equations

The Attempt at a Solution

...$dx/x = ((sin 2θ)/(3+ cos 2θ))dθ$ ,

let $u = (3+cos 2θ)⇒ du/dθ= -2 sin 2θ$
thus

$∫dx/x = -1/2∫du/u$...[/B]are my steps correct?i can solve from here

 

[Simon Bridge]

You noticed that it was 1st order seperable, and proposed a u-substitution for the resulting RHS: well done.
I didn't check your arithmetic - you have to do that yourself - but the reasoning is sound so far.