Solving a Basic Gravity Problem: How Fast Does a Tomato Fall from 100 Feet?

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SUMMARY

The discussion focuses on calculating the time and speed of a tomato falling from a height of 100 feet. The acceleration due to gravity is established as 32 ft/sec². The initial attempt incorrectly applies the formula for displacement, leading to a time of 2.5 seconds for the fall. The correct approach involves using the formula V² = 2gh, which directly relates gravitational potential energy to kinetic energy, providing a more accurate calculation of the tomato's impact speed.

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I feel like an idiot asking this, it's review of a previous course as we start a new quarter, and I KNOW I used to be able to do this... but I don't remember how too. Time to review...

Homework Statement



A tomato is dropped from 100 feet above the ground. At what speed does it hit the ground?
How long does it take to fall the last 100 feet?

Homework Equations



Acceleration due to gravity is 32 ft/sec^2

The Attempt at a Solution



If I recall correctly, delta X = 1/2 at^2
100 = 1/2 32 T^2
200 = 32 T^2
6.25 = T^2
T = 2.5
Tomato hits ground after 2.5 seconds.
So now, plugging that in:
32 (2.5)^2 = 200... which is definitely not right.
 
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TG3 said:
I feel like an idiot asking this, it's review of a previous course as we start a new quarter, and I KNOW I used to be able to do this... but I don't remember how too. Time to review...

Homework Statement



A tomato is dropped from 100 feet above the ground. At what speed does it hit the ground?
How long does it take to fall the last 100 feet?

Homework Equations



Acceleration due to gravity is 32 ft/sec^2

The Attempt at a Solution



If I recall correctly, delta X = 1/2 at^2
100 = 1/2 32 T^2
200 = 32 T^2
6.25 = T^2
T = 2.5
Tomato hits ground after 2.5 seconds.
So now, plugging that in:
32 (2.5)^2 = 200... which is definitely not right.

Doing it your way, the last step would be V = a*t not t2

Otherwise you could take the Potential energy to kinetic energy relationship:

m*g*h = 1/2*m*V2

or

V2 = 2*g*h
 

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