Solving a Frictional Problem with No Given Masses

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Homework Help Overview

The discussion revolves around a problem involving frictional forces between surfaces, specifically focusing on a crate in a pickup truck that is braking. The challenge arises from the absence of given masses in the problem, which complicates the calculation of the coefficient of static friction.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between frictional forces and the coefficient of static friction, questioning how to approach the problem without specific mass values. There is discussion about drawing force diagrams and the implications of assuming a mass for calculations.

Discussion Status

Some participants have provided guidance on the necessity of a force diagram and the concept that masses may cancel out in the equations. Others are attempting calculations based on assumed mass values, leading to discussions about the dimensional nature of the coefficient of friction.

Contextual Notes

Participants note that the problem lacks specific mass values, which is a key constraint in solving for the coefficient of static friction. There is also a reminder that the normal force may not always equal the gravitational force, depending on the context.

python023
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In this section, I am trying to determine frictional forces between surfaces and masses. However, in this type of problem, no masses are given. Here is a type of question:

A crate is carried in a pickup truck traveling horizontally at 15.0 m/s. The truck applies the brakes for a distance of 28.7 m while stopping with uniform acceleration. What is the coefficient of static friction between the crate and the truck bed if the crate does not slide?

I have determined the truck brakes at -3.92 m/s^2. The formula I have for coefficient of static friction is Frictional Force = Coeff. of Friction * Normal Force. However, no forces or masses are given. How can I solve this type of problem?

Thank you
 
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You need to draw your force diagram. You will find that the masses cancel and that the acceleration from friction will be some percentage of acceleration of gravity, and that will be your coefficient.
 
I tried to set the mass of the crate to 100kg. After drawing a force diagram, I'm not sure I am doing it right. Force Normal and the Force of Gravity should equal one another. If Net Force = Mass * Acceleration, and the mass is 100kg*-3.92 m/s, you get a negative net force of -392 N. 392 N/981N(Normal Force) = .400N. Is this the coefficient of friction?
 
Almost ... the Units cancel (392 N / 981 N) = 0.40 , unitless.
The co-efficient of friction is an efficiency , so it is dimensionless.

By the way, Normal Force = gravity Force here, but it often isn't ... watch out!
 

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