Solving a Momentum Problem: Calculating Average Force and Impulse

[rachael]

11 A racing car of mass 2500 kg changes its velocity from
220 km h–1 due south to 200 km h–1 due north in 5.0 s
on a racing track.

c What is the average force applied?
d What is the impulse of this force?
e What is the change in the momentum of the car?

what does part c means?
how do we find the average force applied?

thank you

 

[nrqed]

11 A racing car of mass 2500 kg changes its velocity from
220 km h–1 due south to 200 km h–1 due north in 5.0 s
on a racing track.

c What is the average force applied?
d What is the impulse of this force?
e What is the change in the momentum of the car?

what does part c means?
how do we find the average force applied?

thank you

The average force applied is $F_{average} = {\Delta p \over \Delta t}$, that is, the change of momentum over the time interval over which the change of momentum took place (this is the average form of $F_x = { dp_x \over dt}$ for example).

Patrick