Solving a Piecewise Schrodinger equation

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SUMMARY

The discussion focuses on solving the time-independent Schrödinger equation for a potential well scenario. The equation is expressed as $$-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\psi(x) - V(x)\psi(x) = E\psi(x)$$. The user initially struggles with the boundary conditions in region III, where the potential energy exceeds the particle's energy. A resolution is found by suggesting that the coefficients F and G can be adjusted to satisfy the boundary condition at ##x = a_3##, leading to the wave function $$\psi_{III} (x) = Fe^{-\mu x} + Ge^{\mu x}$$ with specific values for F and G.

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  • Familiarity with boundary conditions in quantum systems.
  • Knowledge of exponential functions and their role in wave functions.
  • Basic concepts of potential wells and energy levels in quantum mechanics.
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Students and researchers in quantum mechanics, particularly those working on problems involving potential wells and the Schrödinger equation.

cc94
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Homework Statement


I was trying to solve the time-independent Schrödinger's equation for this well: http://i.imgur.com/C9QrvkX.png
First I tried to look at cases where the energy of a particle is ##E < V_1##.

Homework Equations


Schrödinger's equation:
$$-\frac{\hbar^2}{2m}\frac{d^2}{dx^2}\psi(x) - V(x)\psi(x) = E\psi(x)$$

The Attempt at a Solution


I thought the normal way to deal with these square barriers is to break the equation up piece-wise and then match the conditions at the boundary. But in region III, there's a problem. Schrödinger's equation requires an exponential solution because ##V_1>E##. The wave function is

$$\psi_{III} (x) = Fe^{-\mu x} + Ge^{\mu x},$$

where ##\mu = \frac{\sqrt{2m(V_1-E)}}{\hbar}##. But the boundary condition requires that at ##x = a_3##, ##\psi_{III} (a_3) = 0##. This isn't possible unless either F = G = 0, or the wave function is actually a sin/cos wave function here. What am I missing?
 
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cc94 said:
But the boundary condition requires that at ##x = a_3##, ##\psi_{III} (a_3) = 0##. This isn't possible unless either F = G = 0, or the wave function is actually a sin/cos wave function here. What am I missing?
Are you sure? How about ##F=\exp \mu a_3## and ## G=-\exp -\mu a_3##?
 
Doh, I didn't think hard enough. Thanks
 

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