Solving a quartic equation for x

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Cocoleia
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Homework Statement


I am trying to solve for x in this equation:
Handwritten equation: x squared over a squared, plus (mx minus mc) squared over b squared, equals 1.


Homework Equations

The Attempt at a Solution


I tried solving it like a quadratic equation.
This is the most simplified I could get it.
Handwritten fraction: numerator a^2(m^2ca ± b√(m^2a^2 − m^2c^2b^2 + 1)) over denominator b^2 + m^2a^2.

Can someone please help me find a simpler expression
 
Cocoleia said:

Homework Statement


I am trying to solve for x in this equation:
View attachment 108531

Homework Equations

The Attempt at a Solution


I tried solving it like a quadratic equation.
This is the most simplified I could get it.
View attachment 108529
Can someone please help me find a simpler expression
Can you please show all of your work and intermediate steps? Thanks. :smile:
 
Cocoleia said:

Homework Statement


I am trying to solve for x in this equation:
View attachment 108531

Homework Equations

The Attempt at a Solution


I tried solving it like a quadratic equation.
This is the most simplified I could get it.
View attachment 108529
Can someone please help me find a simpler expression

Maybe there isn't a simpler expression. Not all simple-looking problems have simple-looking solutions. Anyway, I get a different answer.
 
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A useful habit is to check whether a simple solution to the one expression is also a solution to the other. Your original has the solution x=a=c. That does not appear to be a solution of your final expression.
 
berkeman said:
Can you please show all of your work and intermediate steps? Thanks. :smile:
Handwritten algebra working on lined paper: derivation of x from y = mx - mc and x^2/a^2 + (mx - mc)^2/b^2 = 1, with repeated square-root quadratic-formula steps, some lines crossed out.

and then i just simplified to my final answer
 
Cocoleia said:
and then i just simplified to my final answer

I would have multiplied through the first equation by ##a^2b^2## to get rid of the fractions.
 
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Cocoleia said:
View attachment 108557
and then i just simplified to my final answer
Did you read post #4? You can make further use of this by plugging in the simple solution at various points in your working to see at what point it ceases to be a solution.