Solving a set of nonlinear quadratic equations

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Discussion Overview

The discussion revolves around solving a system of nonlinear quadratic equations represented by the equation ϒϒ'C – ϒα = B, where participants seek methods or algorithms to find the vector ϒ. The conversation includes technical details about the structure of the equations and potential issues related to the values of B and α.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents the equation ϒϒ'C – ϒα = B and requests algorithms or code to solve for ϒ.
  • Another participant points out a potential typing error in the formulation and clarifies that ϒϒ' is a matrix.
  • Some participants discuss the implications of B being a zero vector or a scaled version of ϒ, suggesting that these conditions could simplify the problem.
  • There is contention regarding whether B can be treated as a constant column vector, with some arguing that this leads to inconsistencies in the equations presented.
  • One participant compares the situation to incorrect mathematical statements, emphasizing the need for clarity in the formulation of the equations.
  • References to external materials, such as a paper on Portfolio Theory, are made to support claims about the equations.

Areas of Agreement / Disagreement

Participants express differing views on the validity of the formulation of the equations, particularly regarding the nature of B. There is no consensus on whether the original equation is correct or how to proceed with solving it.

Contextual Notes

Participants note potential issues with dimensionality and the assumptions underlying the equations, but these remain unresolved within the discussion.

Tilfani
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I would like to solve this system, which is a sets of non linear quadratic equations, the system needed to be solved can be expressed in general as follow:

ϒϒ'C – ϒα = B

Where ϒ=(ϒ1,ϒ2,...ϒn)’ is a column vector and ϒ’ its transpose

C=(c1,c2,…,cn)’ and B=(b1,b2,…bn)’ are a columns vector

And α is a reel scalar

I would like to solve for ϒ, with approximatively about 30

Can someone propose me an algorihm/method to solve this system.
also a code to do it wil be very useful.
Bests
 
Last edited:
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Tilfani said:
I would like to solve this system, which is a sets of non linear quadratic equations, the system needed to be solved can be expressed in general as follow:

ϒ’ϒC – ϒα = B

Where ϒ=(ϒ1,ϒ2,...ϒn)’ is a column vector and ϒ’ its transpose

C=(c1,c2,…,cn)’ and B=(b1,b2,…bn)’ are a columns vector

And α is a reel scalar

I would like to solve for ϒ, with approximatively about 30

Can someone propose me an algorihm/method to solve this system.
also a code to do it wil be very useful.
Bests
Y' Y is a scalar, ##\vec Y \cdot \vec Y = |\vec Y|^2##. If you know the value of ##\vec Y \cdot \vec Y## (but don't know the components of ##\vec Y##), you can rewrite the equation above as a system of equations:
##\alpha Y_1 = \vec Y \cdot \vec Y - b_1##
##\alpha Y_2 = \vec Y \cdot \vec Y - b_2##
.
.
.
##\alpha Y_n = \vec Y \cdot \vec Y - b_n##

Divide both sides by ##\alpha## to get
##Y_1 = 1/\alpha (\vec Y \cdot \vec Y - b_1)##
##Y_2 = 1/\alpha (\vec Y \cdot \vec Y - b_2)##
.
.
.
##Y_n = 1/\alpha (\vec Y \cdot \vec Y - b_n)##
 
so we're dealing with real scalars here.
- - - -

So your 'equation' is:

ϒϒ'C – ϒα = B
or

ϒϒ'C = ϒα + B

so you have a real symmetric rank one matrix on the Left Hand side (LHS).

The issue is that every possible c you can choose on the LHS gets mapped to zero or is an eigenvector (i.e. ϒ) or a linear combination of the two aforementioned things. So let's hope that B is either a scaled version of ϒ or else the zero vector. If your B is the zero vector, it should be pretty easy. Otherwise you have problems.

More issues: For starters, why write ϒα + B on the Right hand side... why not just write
##\propto ϒ##
 
StoneTemplePython said:
so we're dealing with real scalars here.
- - - -

So your 'equation' is:

ϒϒ'C – ϒα = B
or

ϒϒ'C = ϒα + B

so you have a real symmetric rank one matrix on the Left Hand side (LHS).

The issue is that every possible c you can choose on the LHS gets mapped to zero or is an eigenvector (i.e. ϒ) or a linear combination of the two aforementioned things. So let's hope that B is either a scaled version of ϒ or else the zero vector. If your B is the zero vector, it should be pretty easy. Otherwise you have problems.

More issues: For starters, why write ϒα + B on the Right hand side... why not just write
##\propto ϒ##
B is nonzero column, there is a way to solve that?
 
Tilfani said:
B is nonzero column, there is a way to solve that?

then ##B \propto ϒ## or this is not an equation
 
StoneTemplePython said:
then ##B \propto ϒ## or this is not an equation
B is a constant.
 
Tilfani said:
B is a constant.

I don't know what this means. Your original post, and a quick dimensional check say B is a a column vector.

What I am trying to tell you is your original post is analogous to

## 2 = 3##

or

## 2 = 3 +x##
for real ## x \geq 0##

this is not an equation. It is just wrong.
 
Yes i mean B is a constant column vector. Do you think that is wrong to?
 
  • #10
You're not hearing me. It is one of the 3 options

option a)
## B = \mathbf 0##

option b)
##B \propto ϒ##

option c)
this is not an equation. It is just wrong.
- - - - -
I have nothing more to say on the matter. Good luck.
 
  • #11
Ok, please look at eq (2 19) page 8 on this link, this paper, maybe some thing wrong.
Portfolio Theory: Origins, Markowitz and CAPM Based Selection - Springer
PDFhttps://www.springer.com › document
 
  • #12
Tilfani said:
Ok, please look at eq (2 19) page 8 on this link, this paper, maybe some thing wrong.
Portfolio Theory: Origins, Markowitz and CAPM Based Selection - Springer
PDFhttps://www.springer.com › document
Please provide the actual link to the document. The link you show is just to the Springer site.
 
  • #13
Mark44 said:
Please provide the actual link to the document. The link you show is just to the Springer site.
Please find enclosed the document. Go to page 7 to see the original problem, the resolution of lagrangian (which may be wrong) lead to equation posted which is (2 19)
 

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