Solving a Stochiometry Question: 2Li + F2 --> 2LiF

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A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
I think I start by dividing 15 g by the molar masses, but is the molar mass
2 x amu of Li and 2 x amu of F?
Thanks
 
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help is hereeeee...

i think you have to first find out what the limiting reactant is. and then use that amount to see how much lithium fluoride forms.
hope this helps :biggrin:
 
SCGirl said:
A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
I think I start by dividing 15 g by the molar masses, but is the molar mass
2 x amu of Li and 2 x amu of F?
Thanks
Correct for fluorine, because it is made up of diatomic molecules (hence, F2), but not lithium, which is monoatomic.

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