Solving a Stochiometry Question: 2Li + F2 --> 2LiF

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To solve the stoichiometry question involving the reaction of lithium and fluorine to form lithium fluoride, first determine the limiting reactant by calculating the moles of each reactant using their molar masses. The molar mass of fluorine should be calculated as F2, while lithium is monoatomic. After identifying the limiting reactant, use its amount to calculate the quantity of lithium fluoride produced. The discussion emphasizes the importance of proper forum categorization for such questions. Understanding these concepts is crucial for accurately predicting the products of the reaction.
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A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
I think I start by dividing 15 g by the molar masses, but is the molar mass
2 x amu of Li and 2 x amu of F?
Thanks
 
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help is hereeeee...

i think you have to first find out what the limiting reactant is. and then use that amount to see how much lithium fluoride forms.
hope this helps :biggrin:
 
SCGirl said:
A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
I think I start by dividing 15 g by the molar masses, but is the molar mass
2 x amu of Li and 2 x amu of F?
Thanks
Correct for fluorine, because it is made up of diatomic molecules (hence, F2), but not lithium, which is monoatomic.

PS: From the next time on, such questions should be posted under the Homework & Coursework forums found near the top of the main page.
 
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