Chemistry Question Solution Stochiometry And Determining The Concentration?

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SUMMARY

The discussion focuses on calculating the concentration of ions after mixing 600.0 mL of 2.00 mol/L Barium nitrate with 100.0 mL of 2.50 mol/L sodium phosphate. The balanced chemical equation is 3Ba(NO3)2 + 2Na3PO4 = Ba3(PO4)2 (solid) + 6NaNO3. The limiting reagent is identified as sodium phosphate, with 0.25 moles available, resulting in 0.375 moles of Barium nitrate consumed. The final concentrations of the ions are determined by dividing the moles of each ion by the total volume of 0.7 liters.

PREREQUISITES
  • Understanding of stoichiometry and limiting reagents
  • Knowledge of molarity calculations
  • Familiarity with chemical equations and balancing
  • Basic concepts of ionic compounds and solubility
NEXT STEPS
  • Calculate the final concentrations of Ba2+ and Na+ ions after the reaction
  • Explore the concept of excess reagents in chemical reactions
  • Review the principles of solubility and precipitation reactions
  • Learn about the application of stoichiometry in real-world chemical processes
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical analysis or laboratory work will benefit from this discussion, particularly those focusing on stoichiometry and solution concentration calculations.

justinh8
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Homework Statement



What is the concentration of all ions after 600.0mL of 2.00 mol/L Barium nitrate is added to 100.0 mL of 2.50 mol/L sodium phosphate.


The Attempt at a Solution


I first wrote down the equation : 3Ba(No3)2 + 2Na3PO4 = Ba3(PO4)2 (solid) + 6NaNO3
I then found the moles using n = c x v.
moles of Ba(No3)2 n = 2 x 0.6L = 1.2 mols
moles of Na3PO4 n = 2.5 x 0.1 = 0.25 mols.

I than found the LR: 0.25 mols Na3PO4 x 3 mols Ba(NO3)2/2Na3PO4 = 0.375 mols Ba(NO3)2

So I have more than i need for barium nitrate so my limiting reagent is sodium phosphate.

Now what i am having trouble with is, is that should i find the excess reagent by doing 1.2 - 0.375 = 0.825 or do i have to find the mols of the solid barium phosphate and then find the limiting reagent using that.. Please help, thanks!
 
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anyone care to help??
 
You are provided with the concentrations and volumes of the reactants. Find out the moles of reactants and the final moles of all the ions as the question says. Then divide the moles by the total volume i.e. 0.7 litres.
 

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