Chemistry Question Solution Stochiometry And Determining The Concentration?

justinh8
Messages
43
Reaction score
0

Homework Statement



What is the concentration of all ions after 600.0mL of 2.00 mol/L Barium nitrate is added to 100.0 mL of 2.50 mol/L sodium phosphate.


The Attempt at a Solution


I first wrote down the equation : 3Ba(No3)2 + 2Na3PO4 = Ba3(PO4)2 (solid) + 6NaNO3
I then found the moles using n = c x v.
moles of Ba(No3)2 n = 2 x 0.6L = 1.2 mols
moles of Na3PO4 n = 2.5 x 0.1 = 0.25 mols.

I than found the LR: 0.25 mols Na3PO4 x 3 mols Ba(NO3)2/2Na3PO4 = 0.375 mols Ba(NO3)2

So I have more than i need for barium nitrate so my limiting reagent is sodium phosphate.

Now what i am having trouble with is, is that should i find the excess reagent by doing 1.2 - 0.375 = 0.825 or do i have to find the mols of the solid barium phosphate and then find the limiting reagent using that.. Please help, thanks!
 
Physics news on Phys.org
anyone care to help??
 
You are provided with the concentrations and volumes of the reactants. Find out the moles of reactants and the final moles of all the ions as the question says. Then divide the moles by the total volume i.e. 0.7 litres.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
13K
Replies
15
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
3
Views
2K
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
6K