Solving a Tricky Calculus Equation: 24 = 10(ex/20 + e-x/20)

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Homework Help Overview

The problem involves solving the equation 24 = 10(ex/20 + e-x/20), which is situated within the context of calculus. Participants are attempting to find the value of x that satisfies this equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various attempts to manipulate the equation, including logarithmic transformations and substitutions. There is mention of using hyperbolic functions and the Quadratic Formula, as well as concerns about the validity of certain algebraic steps.

Discussion Status

The discussion is ongoing, with some participants providing guidance on potential methods to approach the problem, such as suggesting a substitution to simplify the equation. There is acknowledgment of errors in previous attempts, and a participant expresses frustration over a calculator mistake that affected their progress.

Contextual Notes

Some participants question the properties of logarithms and their application in this context. There is also a reference to the need for clarity on the representation of hyperbolic functions, indicating a potential gap in understanding that may affect problem-solving.

Larsani
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I'm reviewing for calculus and I've been stuck on this problem for a couple days. Can't seem to figure it out. I keep coming up with ln2.4 = x - x which is just silly, or x = √(400ln2.4) ≈ 18.7. I know the answer is x ≈ 12.5. But I can't figure out the correct process.

Homework Statement



24 = 10(ex/20 + e-x/20)

Homework Equations





The Attempt at a Solution



2.4 = ex/20 + e-x/20

ln2.4 ≠ x/20 - x/20

I tried using ex/20 = ex - e20 but I don't think this is right either. Came up with

20.69 - ln e-x = x

and this is just another silly answer. I must be forgetting some rule. It seems to me like the variables keep canceling out, which I know can't be right.
 
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Do you know the representations for the hyperbolic functions?
 
I guess not.
 
Larsani said:
I'm reviewing for calculus and I've been stuck on this problem for a couple days. Can't seem to figure it out. I keep coming up with ln2.4 = x - x which is just silly, or x = √(400ln2.4) ≈ 18.7. I know the answer is x ≈ 12.5. But I can't figure out the correct process.

Homework Statement



24 = 10(ex/20 + e-x/20)

Homework Equations





The Attempt at a Solution



2.4 = ex/20 + e-x/20

ln2.4 ≠ x/20 - x/20
The step above is incorrect. There is NO property of logs that allows you to simplify log(A + B) to logA + logB.

Multiply all three terms in the original equation by ex/20. That will give you an equation that is quadratic in form. With a suitable substitution, you can use the Quadratic Formula to solve that equation.
Larsani said:
I tried using ex/20 = ex - e20 but I don't think this is right either. Came up with

20.69 - ln e-x = x

and this is just another silly answer. I must be forgetting some rule. It seems to me like the variables keep canceling out, which I know can't be right.
 
To expand on Mark's idea, if ex/20 = u, then what does the equation change into?
 
Thanks Mark! I had tried multiplying by e^x/20 and using the quadratic forumula but I guess I didn't do it right the first time. Checked the trash can: I made a calculator error and didnt notice it. Hate it when I do something right and then make a little mistake that makes me think I am not doing it right and I end up trying things that I know look wrong. Thanks again.
 

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