Solving Acceleration Problem: Find m/s^2 & Seconds

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SUMMARY

The discussion centers on calculating the acceleration and stopping time of a plane landing on an aircraft carrier. The initial speed of the plane is given as 10 km/hr, which converts to 2.78 m/s. The correct approach involves using kinematic equations to find acceleration and time, specifically the equations x(t) = x0 + v0*t + (1/2)*a*t^2 and v(t) = v0 + a*t. The initial calculations presented were incorrect due to a misunderstanding of the conversion and application of kinematic principles.

PREREQUISITES
  • Understanding of kinematic equations
  • Conversion of units (km/hr to m/s)
  • Basic principles of acceleration and deceleration
  • Familiarity with physics concepts related to motion
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications in motion problems
  • Practice unit conversion techniques, particularly for speed
  • Explore examples of constant acceleration scenarios in physics
  • Review the relationship between distance, speed, and time in motion analysis
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Students studying physics, particularly those focused on motion and kinematics, as well as educators seeking to clarify concepts related to acceleration and deceleration in real-world applications.

bwilhelm
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1. A plane traveling at 10km/hr lands on an aircraft carrier and stops in 25.0m
A. Find the acceleration in m/s^2
B. Find the time it took to stop in seconds




Homework Equations


1km/hr = .278 m/s


The Attempt at a Solution


100(.278)= 27.8 m/s
A. 25-27.8 = 2.8 m/s
B. 8.92 seconds (25/2.8)

Is this anywhere near correct? something seems wrong.
 
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bwilhelm said:
1. A plane traveling at 10km/hr lands on an aircraft carrier and stops in 25.0m
A. Find the acceleration in m/s^2
B. Find the time it took to stop in seconds




Homework Equations


1km/hr = .278 m/s


The Attempt at a Solution


100(.278)= 27.8 m/s
A. 25-27.8 = 2.8 m/s
B. 8.92 seconds (25/2.8)

Is this anywhere near correct? something seems wrong.

When you converted to m/s you used 100km/h instead of 10km/h.

I don't understand how you did part A and B... seems like you're mixing up distance, speed and acceleration.

Remember the plane is undergoing a constant deceleration (or a negative acceleration) and coming to a stop over 25m.

Part A and B involve direct use of kinematics equations... you should have studied these... Can you think of a kinematics equation you can apply in part A? You're trying to find acceleration... you know the distance, the initial velocity, and the final velocity. There's an equation you can use.
 
Not near correct. 27.8 m/s is ok, though. Consider using kinematic equations like x(t)=x0+v0*t+(1/2)*a*t^2 and v(t)=v0+a*t. Can you start the problem?
 

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