Solving an Unsolved Math Problem: Ring A & Polynomials

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The discussion addresses the question of whether a polynomial of degree 2 can equal a polynomial of degree 4 within a ring A. It concludes that while it is impossible for two polynomials of differing degrees to be equal, they can represent the same polynomial function under certain conditions. An example provided is from the ring of polynomials over the field of integers modulo 2, specifically using the polynomials \( p(x) = x^2 \) and \( q(x) = x^4 \), which yield the same function in this context.

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Fernando Revilla
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I quote an unsolved problem posted in another forum on December 5th, 2012.

Is there any ring A such that in A[x] some polynomial of degree 2 is equal to a polynomial of degree 4? Can you give me an example and explain how this could be true. Thanks in advance!
 
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It is not possible. According to the formal definition of polynomial, if $p$ has degrre $2$ and $q$ degrre 4 then

$$p=(a_0,a_1,a_2,0,\ldots,0,\ldots)\qquad (a_2\neq 0)\\ q=(b_0,b_1,b_2,b_3,b_4,0,\ldots,0,\ldots)\quad (b_4\neq 0)$$

so, $p\neq q$. Another thing is that if $p$ and $q$ can determine the same polynomical function, and the answer is affirmative. For example, choose in $\mathbb{Z}_2[x]$ the polynomials $p(x)=x^2$ and $q(x)=x^4$.
 

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