Finding reaction forces on a 25 kg beam with pin and roller supports

[wilson11]

Homework Statement

As shown, a roller at point A and a pin at point B support a uniform beam that has a mass 25.0 kg . The beam is subjected to the forces f1 = 50.0N and f2= 79.0N . The dimensions are l1= 0.750m and l2= 2.30m . (Figure 2) What are the magnitudes and of the reaction forces and at points A and B, respectively? The beam's height and width are negligible.

Please see attachment for figure.

Homework Equations

The Attempt at a Solution

(79*cos(15)*3.05)+(50*0.75) = Rb *3.05
Rb=88.6

Ra * sin(53.13010)*3.05 = 50*2.3
Ra=47.1311

I am not sure if this is how you do this type of question..?
Also the answers are not correct as when I go to see if they are correct they come back as incorrect. The ansers i have tryed which are incorrect are, Fa = 47.1 Fb=88.6

 

[phinds]

Uh ... what attached figure is that ?

 

[SammyS]

Homework Statement

As shown, a roller at point A and a pin at point B support a uniform beam that has a mass 25.0 kg . The beam is subjected to the forces f1 = 50.0N and f2= 79.0N . The dimensions are l1= 0.750m and l2= 2.30m . (Figure 2) What are the magnitudes and of the reaction forces and at points A and B, respectively? The beam's height and width are negligible.

Please see attachment for figure.

Homework Equations

The Attempt at a Solution

(79*cos(15)*3.05)+(50*0.75) = Rb *3.05
Rb=88.6

Ra * sin(53.13010)*3.05 = 50*2.3
Ra=47.1311

I am not sure if this is how you do this type of question..?
Also the answers are not correct as when I go to see if they are correct they come back as incorrect. The answers i have tryed which are incorrect are, Fa = 47.1 Fb=88.6

There is no attached figure.

 

[wilson11]

It says that I have already uploaded the image. I have also posted this question in a different forum. Can you please have a look at this one.

https://www.physicsforums.com/showthread.php?t=637033

Above is the same question with figure.

Sorry for the confustion.

Thanks