Solving Calc-Based Physics Problems: Object Position and Velocity at t=2s

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SUMMARY

The discussion focuses on solving a physics problem involving an object's position and velocity at t=2 seconds, defined by the equation r=12ti+(15t-5.0t^2)jm. The position at t=2 seconds is calculated by substituting t=2 into the equation, yielding r(2) = 12(2)i + (15(2) - 5.0(2)^2)j = 24i + 10j. The average velocity from t=0 to t=2 seconds is determined using the formula V=change in r/change t, while the instantaneous velocity at t=2 requires the derivative, resulting in V=12i+(15-10(2))j = 12i - 5j.

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Homework Statement



An objects position as a function of time is given by r=12ti+(15t-5.0t^2)jm, where t is time in seconds. A: what is the onject's position at t=2 s. B what is its average velocity in the interval from t=o to t=2.0s.C: what is its instantaneous velocity at t=2?

Homework Equations



Derivative:12i+(15-10t)

V=change in r/change t

The Attempt at a Solution


A: simply plug 2 in for t in the original equation
B:take the derivative of the problem and plug in 2 for t
C: Dont really know . . .
 
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possum30540 said:
A: simply plug 2 in for t in the original equation
OK.
B:take the derivative of the problem and plug in 2 for t
No derivatives needed, since you want the average velocity. (Use the formula you quoted.)
C: Dont really know . . .
Here's where you need a derivative.
 

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